That picture is upside down. - User 12 ∑ n = 0 ∞ ( − 3 ) − n ( 2 n + 1 ) − 1 {\displaystyle \scriptstyle {\sqrt {12}}\sum _{n=0}^{\infty }(-3)^{-n}(2n+1)^{-1}} 00:58, 6 March 2009 (EST)